Assign to step changes timing about bschaffl HOT 5 CLOSED

Both is supported. Assignment and timing. Therefore two sliders.

from bschaffl.

Yes, that's what I thought, but Assign changes the timing for me.

from bschaffl.

This shouldn't happen.

from bschaffl.

Let's take your SchafflDemo as an example (with assignment on and range set to a low value of some 0.1). Input 16 symmetric short ticks per bar. This means that note 1 starts at bar position 0.000, note 2 at 0.0625, note 3 at 0.125, ...

You divided each bar into 11 steps. This means that each input step takes some 0.09 bars.

Therefore note 1 and note 2 drops into step 1 and note 3 into step 2... Note 1 and note 2 are amplified with amp of step 1 (and you can easily hear both of them). Note 3 is amplified with amp of step 2 (you can gently hear). Note 1 and note 2 are stretched to 0.0112-0.0291 and 0.0832-0.1012, respectively (latency = 0.0112). Note 3 is squeezed to 0.1438-0.1565.

The data and what I hear fit nicely to the theory. Thus, it works.

But there are two pitfalls. (1) If you switch off assignment, the note can drop into the wrong step. As you know. And this may sound like a timing change. Especially if all notes have the same pitch. (2) If the range is too high, a middle note can be assigned to the next step. This may easily happen with your 16/11 pattern. And also this may sound like a time change.

from bschaffl.

Ah, yes, now I get it.
My mental model was indeed off, and yes, I was hearing velocity changes and mistaking them for timing changes.

Sorry for the noise!

from bschaffl.