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QMap <QString, QList<QString>> x;
x.insert("a", QList<QString>() << "content1" << "content2");

这个 QMap 无法转换成json

C++ 版本依赖是怎样的?是否必须 C++11 及以上的版本支持？

error:
x2struct-master/xtypes.h:90:65: error: 'strptime' was not declared in this scope
if (0 != strptime(str.c_str(), "%Y-%m-%d %H:%M:%S", &ttm)) {
^
fix used :
#if defined(__WIN32__)
#ifndef WINDOWS
#define WINDOWS
#endif

in order to fix it :
warn on README that you have to define WINDOWS on windows before importing the library

or

use __WIN32__ instead of WINDOWS

time_t is defined as these below in Linux:

time_t 
(in time_t.h) --> typedef __time_t time_t 
(in types.h) --> __STD_TYPE __TIME_T_TYPE __time_t; 
(in typesizes.h) --> #define __TIME_T_TYPE		__SYSCALL_SLONG_TYPE

and finally

#if defined __x86_64__ && defined __ILP32__
# define __SYSCALL_SLONG_TYPE	__SQUAD_TYPE
# define __SYSCALL_ULONG_TYPE	__UQUAD_TYPE
#else
# define __SYSCALL_SLONG_TYPE	__SLONGWORD_TYPE
# define __SYSCALL_ULONG_TYPE	__ULONGWORD_TYPE
#endif

for different platforms.

However, on macOS (at lease in macOS Catalina and 10.14), time_t is defined as long (from the compiler error message)...

Tl; Dr:
Seems that x2struct has a missing convert of type long， https://github.com/lhy0403/Qv2ray/commit/bcb328e772b50e7896e142450bd89dc9fcf939a0/checks?check_suite_id=379416319#step:6:321

你好：
我在声明的结构体中调用了XTOSTRUCT，但是报错了。提示宏定义TOX_ 和 X_STRUCT_L1是未声明的标识符。代码跟进去文件x2struct.hpp，果然没有找到这两个宏定义。宏定义TOS_也没有找到。
这是怎么回事啊？

struct Item 
{
  string label;
  string type;
  string value;
  vector<string> choices;
  XTOSTRUCT(M(label,type, value), O( choices));
};

代码如下

  map<string, Item> members;
  Item test1;
  test1.label = "Canon";
  test1.type = "choice";
  test1.value="Manual";
  test1.choices.resize(2);
  test1.choices[0]="TV";
  test1.choices[1]="AV";
  members["autoexposuremode"] = test1;
  
  Item test2;
  test2.label = "Bracket";
  test2.type = "string";
  test2.value="0";
  members["bracketmode"] = test2;

  string json = x2struct::X::tojson(members); // 结构体转json
  cout << json << endl;

运行结果如下

{
	"autoexposuremode": {
		"label": "Canon",
		"type": "choice",
		"value": "Manual",
		"choices": ["TV", "AV"]
	},
	"bracketmode": {
		"label": "Bracket",
		"type": "string",
		"value": "0",
		"choices": []
	}
}

希望choice，有值就显示，没值不显示

{
	"autoexposuremode": {
		"label": "Canon",
		"type": "choice",
		"value": "Manual",
		"choices": ["TV", "AV"]
	},
	"bracketmode": {
		"label": "Bracket",
		"type": "string",
		"value": "0"
	}
}

• 还有一种情况，就是value值可能是int类型的，比如日期，不是字符串的，不知道能不能

{
    "streamSettings": {
        "headers": null,
        "network": "ws",
        "security": "tls",
        "tlsSettings": {
            "allowInsecure": true,
            "serverName": null
        },
        "wsSettings": {
            "path": "/admin"
        }
    }
}

会出现 SIGABORT 错误

example.h(91): error C2664: “bool x2struct::JsonReader::convert(const char *,float &)”: 无法将参数 2 从“char [16]”转换为“std::string &”

eg
定义：
struct input
{
std::string name;
std::string id;
XTOSTRUCT(M(name,id));
};
json：
{
"name": "Tom",
"id":1
}
id 类型为int而不是string
没有错误，没有异常。
这个问题比较严重

It seems std::wstring is not supported by the x2struct library. Is there any plan to implement that?

I am using boost::posix_time::ptime for storing datetime in my struct, but I am not able serialize the struct to json.

Can't support array, but vector is supported. Are there any ways to support array directly.

typedef struct _User
{
std::string name;
}User;

typedef struct _UserList
{
std::vectorstd::string userVec;
}UserList;

struct ConnectionProp{
int connectionId;
std::string connectionName;
double timeout;
XTOSTRUCT(M(connectionId,timeout),O(connectionName));
};

ConnectionProp x;
x2struct::X::loadjson(decodedstr, x, false);

In ConnectionProp object, connectionName property is getting a value of "".

Json is :"{"connectionId":3,"connectionName":"JAY","timeout":3.55566}

project.cpp:15:5: error: use of undeclared identifier 'X_STRUCT_L1_TOX'
x2struct.hpp:780:54: note: expanded from macro 'XTOSTRUCT'

I have modified your code to make it meet and I would like to be contributor

{"testVec":["key":null]}

打印：
Parse json string [{"testVec":["key":null]}] fail. :null]}

非常感谢作者提供这么好的库，因为前端这块要求的json是多了个反斜杠的{"aid":"1","cid":"1","cid_url":"11","time_stamp":"1","status":"1","time_stamp":"1","pic_name":"1","pic_data":"","data":[{"frame_id":"1","time_stamp":"1","alertFlag":"1","headInfo":[{"x":123,"y":123,"width":123,"height":123,"numOfHelmet":"1","color":"1"}]}]}，但是这个库转json后是不带反斜杠的，请问如果有重新实现tojson这个函数要在哪里改

Hello, I have no problem in using the C + + standard type. Now I have customized the QT qstring to work, but when I want to use QT's qlist, I can't compile it, and the error "error c2039:" struct_to_str ": not a member of" qlist < T > ", I rewrite the conversion function. This is the" template < typename T >

JsonWriter& convert(const char*key, QList&data) {

x2struct_set_key(key);

this->array_begin();

for (size_t i=0; i<data.size(); ++i) {

this->convert("", data[i]);

}

this->array_end();

return *this;

}

During my program I run a query and I get this result in a string
{ "ok": true, "result": { "message_id": 109, "from": { "id": 3456789, "is_bot": true, "first_name": "ghhdhdsh", "username": "hbdhbhbdh" }, "chat": { "id": 5678, "first_name": "ghj", "last_name": "ghj", "username": "ghj", "type": "private" }, "date": 1606112895, "text": "ddd" } }

So I created some structures
`
struct from {
int id;
bool is_bot;
string first_name;
string username;
XTOSTRUCT( O(id, is_bot,first_name,username));
};

struct chat{
int id;
string first_name;
string last_name;
string username;
string type;
XTOSTRUCT( O(id, first_name,last_name,username,type));
};

struct result: public from,chat{
int message_id;
int date;
string text;
XTOSTRUCT(I(from,chat), O(message_id, date, text));
};

struct retour: public result {
bool ok;
XTOSTRUCT(I(result), O(ok));

};
`

And I want to do something like

if (retour.ok){ cout<<retour.result.chat.username<<" has received the message"; }

How can I do that, I've got some errors.
Thank you

I want to serialize array of struct to json I.E. BestFive_copy Best5Sell[20]; Where BestFive_copy is my struct.I cannot use vector for some reason. Xtostruct is not able to serialize array of struct to json.

What is the open source LICENSE for this project?
I want to use it in a project having license GPLv3, I'm not sure what your license is.

您好，请问是否不支持 xml的属性字段

I am trying with bool datatype and i have also passed variable in optional field but xhas method returns 0 and when i evaluate the struct the bool variable contains numeric value..is there any issue with bool datatype?

如果结构体里有char,就不支持了,该怎么改

Where is this function?

我的同事正在使用你的库解析json，他一直坚持你的库无法解析嵌套json，并要求我将嵌套的Object转为String。但我希望数据可以按照json的标准形式进行传输，我不是C++程序员，阅读你的源码有些困难，
所以我希望得到你的帮助。

我坚持的结构：

{
    "errorCode": 0,
    "message": "",
    "data": {
        "timestamp": 1531710826,
        "collections": [
            {
                "temperature": 26.7,
                "mac": "ABCDEF",
                "humidity": 75.1
            },
            {
                "temperature": 25.9,
                "mac": "ABCDE2",
                "humidity": 74.6
            
        ],
        "address": "DEFAB"
    }
}

他所坚持的结构：

{
    "errorCode": 0,
    "message": "",
    "data": "{\"timestamp\": 1531710826,\"collections\": [{\"temperature\": 26.7,\"mac\": \"ABCDEF\","humidity": 75.1},{\"temperature\": 25.9,\"sensorMac\": \"ABCDE2\",\"humidity\": 74.6],\"address\": \"DEFAB\"}"
}

代码：
struct User
{
int64_t id;
string name;
string mail;
XTOSTRUCT(O(id, name, mail));
};

User user;
user.id = 1;
user.name = "Jack";
string json1 = x2struct::X::tojson(user);
std::cout << json1 << std::endl;

当前输出结果：
{"id":1,"name":"Jack","mail":""}

期望输出结果：
{"id":1,"name":"Jack"}

当结构提成员超过120个时候,编译失败

I am marshalling my struct i.e. converting struct to byte, and sending it to .Net, But when i include XTOSTRUCT(O(Field1,Field2) in my struct size get changed. Due to which, i get wrong structure on .NET side. Do you have any other way apart from declaring XTOSTRUCT field in struct.

我用Qt写了一个从xml直接转为你的c++结构体代码的程序
但是我无法联系到你 也就无法提交给你
麻烦给个联系方法

[email protected] 这个是我的

data
{
"a": "1",
"extend": {"b": "1", "c": "1", "d": "1", "e": "1", "f": "1", }
}
像这样的 extend 字段，是扩展字段，不知道具体的 字段 有哪些，只是将这个字段做一个转发。
这种情况能不能支持。

我这边用其他 json 库，是直接把 extend 解析成 string 类型