Comments (2)
That has nothing to do with ClassFixture or NSubstitute.
Your test is just wrong.
By using the ClassFixture you have only one instance of your substitute for both tests.
So your first tests sets up the substitute´s Validate function to return true AND calls CheckIfNumberExists. This of course leads to ca call of Exists.
Then your second test runs. You change the Validate to return false AND call CheckIfNumerExists a second time. This of course leads to no call of Exists.
But then you check the number of calls to Exists. Of course the number of calls is 1 if you run both tests. But you expect it to be zero. Therefore the 2nd test fails.
Just change your test like this:
public class Tests
{
private readonly Fixture _fixture;
public Tests()
{
_fixture = new Fixture();
}
//1.
[Fact]
public void ExistsIsCalledWhenValidationIsSuccessful()
{
//first we make sure that Validate() passes so that Exists() gets called
_fixture.SharedSubstitute
.Validate(Arg.Any<int>())
.Returns(true);
//act:
_fixture.App.CheckIfNumberExists(1);
//then we test that the substitute received a call to Exists()
_fixture.SharedSubstitute.Received().Exists(Arg.Any<int>());
}
//2.
[Fact]
public void ExistsIsNotCalledWhenValidationFails()
{
//now we pretend that Validate() fails, i.e. returns false.
_fixture.SharedSubstitute
.Validate(Arg.Any<int>())
.Returns(false);
//act:
_fixture.App.CheckIfNumberExists(1);
//we shouldn't expect a call to Exists()
_fixture.SharedSubstitute.DidNotReceive().Exists(Arg.Any<int>());
}
}
and it works, regardless of running both or only one test.
But what you experienced in your version is just by design
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That makes total sense, looks like I failed to consider that. Thanks for the response!
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