How to define Package Name arg about ros2_simrealrobotcontrol HOT 5 OPEN

Try 'ros2srrc_execution' as the package name. This is the place where the program 'ur3' lies

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Thanks for your answer. This seems to work. What else do I need to launch to start the action server? Something like:
ros2 launch ros2srrc_ur3_gazebo

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There were some changes to the launch files and I dont know exactly what the launch command should look like because Im using an older version.
But I looked into the new files and you can try this:
For a real robot: ros2 launch ros2srrc_launch bringup_ur.launch.py
For a simulation: ros2 launch ros2srrc_launch simulation.launch.py

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Thanks for your help. I am now able to launch a robot simulation using:
ros2 launch ros2srrc_launch simulation.launch.py package:="ros2srrc_ur3" config:="ur3_2" Gazebo opens as expected, but when trying to
ros2 action send_goal -f /Move ros2srrc_data/action/Move "{action: 'MoveL', movel: {x: 0.00, y: 0.00, z: 0.00}, speed: 1.0}"
I am still getting "Waiting for action server to become available"

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What does work though is:
ros2 launch ros2srrc_launch moveit2.launch.py package:="ros2srrc_ur3" config:="ur3_2" (which also launches gazebo)
and
ros2 action send_goal -f /Move ros2srrc_data/action/Move "{action: 'MoveJ', movej: {joint1: 10.00, joint2: 0.00, joint3: 0.00, joint4: 0.00, joint5: 0.00, joint6: 0.00}, speed: 1.0}
which does the job for me.

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