The docker_opencor_run_model's discuss from hsorby

docker_opencor_run_model's Issues

application does not return non-zero code upon failure

Application run does return non-zero code upon failure.

Steps to reproduce

Running w/o arguments displays help and exit code 1

$ docker run hsorby/opencor-python
...
$ echo $?
1

Running w/ arguments runs through and returns exit code 0

$ docker run hsorby/opencor-python 1000.0
... [json result in stdout] ...
$ echo $?
0

Running w/ an invalid input runs though, reports error message in the std::err BUT still returns exit code 0

$ docker run hsorby/opencor-python 5
Traceback (most recent call last):
  File "run_model.py", line 39, in <module>
    main(period)
  File "run_model.py", line 21, in main
    s.run()
RuntimeError: std::runtime_error: at t = 7.89335, mxstep steps taken before reaching tout
$ echo $?
0

In this case, the expected behavior would be to get a non-zero. This way, the client can detect that something went wrong and e.g. show the user the std::err

Some insight

In order to understand better this, I built myself the image and tagged as opencor-python:dev, run the container and executed the command in the entrypoint.sh.

$ docker run -it --entrypoint /bin/bash opencor-python:dev

I noticed that i can reproduce the same in the executable

root@f801628872b5:/home/opencor# ./OpenCOR-2019-05-23-Linux/bin/OpenCOR -c PythonRunScript::script run_model.py 5
Traceback (most recent call last):
  File "run_model.py", line 39, in <module>
    main(period)
  File "run_model.py", line 21, in main
    s.run()
RuntimeError: std::runtime_error: at t = 7.89335, mxstep steps taken before reaching tout
root@f801628872b5:/home/opencor# echo $?
0

See that python interpreter, would return 1 if there is an exception raised:

root@f801628872b5:/home/opencor# OpenCOR-2019-05-23-Linux/python/bin/python -c "raise Exception"
Traceback (most recent call last):
  File "<string>", line 1, in <module>
Exception
root@f801628872b5:/home/opencor# echo $?
1

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