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加法方案:确认门限以及对应的两个多项式(下面对应的多项式是y1 = 2 * x ^ 2 - 3 * x + 4, y2 = x ^ 2 + 5 x - 6,所以通过多项式分发给每个人两个值,最后通过3个人的子秘密和恢复除4 + -6 = - 2)-> 给每个分发子秘密值 -> 通过3个人的子秘密值和使用拉格朗日恢复出-2(两个多项式的常数项和)
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乘法方案:确认门限以及对应的两个多项式-> 给每个分发子秘密值 -> 每个人再通过分发的子秘密值乘积为常数项生成自己的多项式->用自己的多项式给每个人再次进行分发(代码里的C矩阵)->计算lamda向量(每个人都可以计算) ->根据计算的lamda向量和每个人手里拥有的向量求每个人的最终拥有的子秘密值-> 通过3个人的子秘密值和使用拉格朗日恢复出-24(两个多项式的常数项积)
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