Git Product home page Git Product logo

v3-admin's People

Stargazers

 avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar  avatar

Watchers

 avatar  avatar  avatar  avatar  avatar  avatar

v3-admin's Issues

路由中alwaysShow作用没太明白

// 当一个路由下面的 children 声明的路由大于1个时,自动会变成嵌套的模式
// 只有一个时,会将那个子路由当做根路由显示在侧边栏
// 若想不管路由下面的 children 声明的个数都显示你的根路由
// 可以设置alwaysShow: true,这样就会忽略之前定义的规则,一直显示根路由
alwaysShow: true

看文档我以为是把根路由下的子路由放到侧边栏,和监控,权限管理菜单同级别显示,但是设置了true和false都没变.
没办法实现,我又自己写了代码实现的.

    <template v-if="!alwaysShowRootMenu && theOnlyOneChild && !theOnlyOneChild.children">
       <SidebarItemLink v-if="theOnlyOneChild.meta" :to="resolvePath(theOnlyOneChild.path)">
        <!-- 原代码 -->
      </SidebarItemLink>
    </template>

    <template v-else>
      <template v-if="!alwaysShowRootMenu && childrenShowOut">
        <SidebarItemLink v-for="child in childrenShowOut" :key="child?.path" :to="resolvePath(child?.path)">
           <!-- 原代码 -->
        </SidebarItemLink>
      </template>
      <el-sub-menu v-else :index="resolvePath(item.path)" popper-append-to-body>
        <!-- 原代码 -->
      </el-sub-menu>
    </template>
const childrenShowOut = computed(() => {
  if (showingChildNumber.value <= 1) {
    return null
  }
  // 把根目录下的路由提取到一级菜单
  if (props.item.path !== '/') return null
  if (props.item.children) {
    return props.item.children.filter(item => {
      return item
    })
  }
  return { ...props.item, path: '' }
})

ts我不熟, v-for="child in childrenShowOut" 会报警告,不知道怎么解决....

第二次请求/users/info接口会报跨域错误

image

登录的时候会请求一次/users/info接口,此时是没问题的,但是我登录上以后,如果再刷新一次页面,还会请求/users/info接口,此时就会报跨域错误,并且我仔细对照了options请求,发现参数是一模一样的。

第一次option:
image
第一次post:
image
第二次option:
image
第二次post:
image

Recommend Projects

  • React photo React

    A declarative, efficient, and flexible JavaScript library for building user interfaces.

  • Vue.js photo Vue.js

    🖖 Vue.js is a progressive, incrementally-adoptable JavaScript framework for building UI on the web.

  • Typescript photo Typescript

    TypeScript is a superset of JavaScript that compiles to clean JavaScript output.

  • TensorFlow photo TensorFlow

    An Open Source Machine Learning Framework for Everyone

  • Django photo Django

    The Web framework for perfectionists with deadlines.

  • D3 photo D3

    Bring data to life with SVG, Canvas and HTML. 📊📈🎉

Recommend Topics

  • javascript

    JavaScript (JS) is a lightweight interpreted programming language with first-class functions.

  • web

    Some thing interesting about web. New door for the world.

  • server

    A server is a program made to process requests and deliver data to clients.

  • Machine learning

    Machine learning is a way of modeling and interpreting data that allows a piece of software to respond intelligently.

  • Game

    Some thing interesting about game, make everyone happy.

Recommend Org

  • Facebook photo Facebook

    We are working to build community through open source technology. NB: members must have two-factor auth.

  • Microsoft photo Microsoft

    Open source projects and samples from Microsoft.

  • Google photo Google

    Google ❤️ Open Source for everyone.

  • D3 photo D3

    Data-Driven Documents codes.