Comments (5)
The easiest way to do this is to use a ref:
<ReactForm ref={el => this.form = el}>
// Somewhere else in the parent component
this.form.submitForm()
Does that work for you?
from form.
@tannerlinsley this has stopped working in v2
, submitForm
is not a function which I can access after creating a ref
to the form, but getApi
should be used instead.
from form.
Thank you for the response!
from form.
Thanks, wouldn't know what to do otherwise (partly because I've never used ref
property in React). @tannerlinsley I think it would be worth adding to the documentation.
from form.
from form.
Related Issues (20)
- onChangeAsyncDebounceMs shouldn't be called when calling form.submit
- Nested array doesn't work in react strict mode HOT 1
- Values in nested arrays do not get updated properly
- [Tracking] Refactors prior to 1.x
- Array fields do not run onChange validation HOT 2
- Doubly nested array subfield infers `never` for value type HOT 8
- Mismatch in array handling between useForm and FormData HOT 3
- Error using useState & form.setFieldValue HOT 7
- Add a way to display only one error for a field HOT 3
- Calling `createFormFactory<FormData>` and using a validator adapter throw TS errors HOT 1
- onChangeAsyncDebounceMs not properly debouncing HOT 1
- TanStack/Angular - Error when resetting the form HOT 1
- Missing error when validating via form options instead of via field HOT 3
- Factory `onSubmit` function not invoked whenever factory.useForm gets provided with `onSubmit` itself HOT 2
- Unable to read properties in nested array table HOT 2
- Nested Values Disappear when using StrictMode HOT 5
- onMount Error is not revalidated when the user changes the input HOT 2
- server actions example errors when using zod adapter HOT 1
- Cannot infer types on arrays of union of objects HOT 1
- Moving subfields of array field mix their values HOT 1
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