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eliphatfs avatar eliphatfs commented on August 24, 2024 1

I apologize for misunderstanding the question as this is the output. There might be a part not in the FOV, but for most objects, they do not look like spheres, or is not that like spheres. They are thus still fully visible in the FOV. This makes pixel utility and hence effective resolution higher for most objects. For spheres there will be a small part outside the FOV.

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Dustinpro avatar Dustinpro commented on August 24, 2024

It is normalized to fit into a sphere with radius=.5. The fixed camera distance is 0.5 / np.tan(np.radians(30/2)).

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bluestyle97 avatar bluestyle97 commented on August 24, 2024

@Dustinpro Thanks for your reply!

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WilliamHaiweiGu avatar WilliamHaiweiGu commented on August 24, 2024

@Dustinpro But if the camera distance is radius / np.tan(np.radians(30/2)), there will be a part of the sphere not in the FOV (the black area in the graph below)
image
So is the distance radius / np.sin(np.radians(30/2))?

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eliphatfs avatar eliphatfs commented on August 24, 2024

Yes, there might be a part not in the FOV. This is by design as a data distribution augmentation to enhance the capabilities of the model.

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