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mysql-protocol's Issues

进制转化的一些疑惑

public static final void writeUB3(ByteBuffer buffer, int i) {
		buffer.put((byte) (i & 0xff));
		buffer.put((byte) (i >>> 8));
		buffer.put((byte) (i >>> 16));
	}

不明白,为什么int转为byte类型还需要用 i&0xff呢?
我的理解是因为(byte)的强制转化是针对int类型的低8位的,所以就算i没有进行 &0xff的操作,也是不会影响到该值的吧。
所以高字节的int转低字节的byte是不是可以写成:

public static final void writeUB3(ByteBuffer buffer, int i) {
		buffer.put((byte) (i) );
		buffer.put((byte) (i >> 8));
		buffer.put((byte) (i >> 16));
	}

BufferUtil相关类疑惑

public static final void writeLong(ByteBuffer buffer, long l) {
buffer.put((byte) (l & 0xff));
buffer.put((byte) (l >>> 8));
buffer.put((byte) (l >>> 16));
buffer.put((byte) (l >>> 24));
buffer.put((byte) (l >>> 32));
buffer.put((byte) (l >>> 40));
buffer.put((byte) (l >>> 48));
buffer.put((byte) (l >>> 56));
}
举这个方法的列子,为什么使用这些移位操作,比较疑惑。为什么是8 16 24 32 40 48 56,谢谢。

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