幸运转盘
Android 抽奖转盘的实现，如下图所示：
## 点击按钮滚动 ## 
## 随手势滚动 ## 
## 滚动到指定区域 ## /** * 开始转动 * @param pos 如果 pos = -1 则随机，如果指定某个值，则转到某个指定区域 */ public void startRotate(int pos){
int lap = (int) (Math.random()*12) + 4;
int angle = 0;
if(pos < 0){
angle = (int) (Math.random() * 360);
}else{
int initPos = queryPosition();
if(pos > initPos){
angle = (pos - initPos)*60;
lap -= 1;
angle = 360 - angle;
}else if(pos < initPos){
angle = (initPos - pos)*60;
}else{
//nothing to do.
}
}
## 更多信息 ## [http://blog.csdn.net/yanghuinipurean/article/details/52251107](http://blog.csdn.net/yanghuinipurean/article/details/52251107)
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