Comments (6)
您好,能将报错时候的现场参数大概提供给我一下么?
from log-record.
您好,能将报错时候的现场参数大概提供给我一下么?
使用出错的案例
@PutMapping(value = "/edit")
@OperationLog(bizId = "'sysConfig'", bizType = "'edit'", msg = "#_DIFF(#oldObject, #newObject)", extra = "#_DIFF(#oldObject, #newObject)")
public Result<?> edit(@RequestBody SysConfig sysConfig) {
LogRecordContext.putVariable("oldObject", sysConfigService.getById(sysConfig.getId()));
sysConfigService.updateById(sysConfig);
LogRecordContext.putVariable("newObject", sysConfig);
return Result.OK("编辑成功!");
}
Entity
/**id*/
@TableId(type = IdType.ASSIGN_ID)
@ApiModelProperty(value = "id")
private java.lang.String id;
/**编码*/
@Excel(name = "编码", width = 15)
@ApiModelProperty(value = "编码")
private java.lang.String code;
/**内容*/
@Excel(name = "内容", width = 15)
@ApiModelProperty(value = "内容")
private java.lang.String content;
/**备注*/
@Excel(name = "备注", width = 15)
@ApiModelProperty(value = "备注")
private java.lang.String remark;
/**是否开启*/
@Excel(name = "是否开启", width = 15, dicCode = "yn")
@Dict(dicCode = "yn")
@ApiModelProperty(value = "是否开启")
private java.lang.String status;
/**创建人*/
@ApiModelProperty(value = "创建人")
private java.lang.String createBy;
/**创建日期*/
@JsonFormat(timezone = "GMT+8",pattern = "yyyy-MM-dd HH:mm:ss")
@DateTimeFormat(pattern="yyyy-MM-dd HH:mm:ss")
@ApiModelProperty(value = "创建日期")
private java.util.Date createTime;
/**更新人*/
@ApiModelProperty(value = "更新人")
private java.lang.String updateBy;
/**更新日期*/
@JsonFormat(timezone = "GMT+8",pattern = "yyyy-MM-dd HH:mm:ss")
@DateTimeFormat(pattern = "yyyy-MM-dd HH:mm:ss")
@ApiModelProperty(value = "更新日期")
private java.util.Date updateTime;
/**所属部门*/
@ApiModelProperty(value = "所属部门")
private java.lang.String sysOrgCode;
from log-record.
因为我在使用Date类型的属性的时候都会有@DateTimeFormat
,所以我直接在对比之前把此类型的属性根据@DateTimeFormat
的pattern值转成了字符串进行对比,希望有更好的解决方案
from log-record.
我简单优化了一下,把版本升级至 1.5.0-SNAPSHOT 看下是否修复。过两天会发正式版本
from log-record.
我自行复现了,并且验证了下是OK了
from log-record.
正式版本1.5.0,有问题重开issue
from log-record.
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from log-record.