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awesome-static's Issues

如果url中出现queryString那么url解析会失败

文件 main.js 中22行 正则会导致解析失败 可以替换为
result = new RegExp("^/" + route + "([^\?]*)").exec(url);

有个问题 ,请教一下,如果用户访问

http://www.domain.com/demo/

http://www.domain.com/demo

这两个网站 第一个成功

第二个网站/demo 将不会解析为路径. /demo被解析为文件了. 这个该如何补救??

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