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큰 수의 법칙
가장 큰 수를 K번 더하고 두 번째로 큰 수를 한번 더하는 연산을 반복하면 된다
# 큰 수 * K + 두 번째로 큰 수의 수열이 반복된다 즉 k+1인 수열이 m//(k+1) 만큼 반복되고,
# m%(k+1) 만큼 큰 수가 더 더해지게 된다.
#가장 큰 수는 m//(k+1) *k + m % (k+1) 만큼 더해지고
#두 번째로 큰 수는 m에서 큰 수가 더해진 횟수를 뺀 만큼 더해지게 된다.
n,m,k = map(int,input().split(" "))
numbers = list(map(int, input().split(" ")))
numbers.sort(reverse= True)
first = numbers[0]
second = numbers[1]
count = int(m/(k+1)) * k
count += m % (k+1)
answer = 0
answer += count*first
answer += (m-count)*second
print(answer)
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