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mhchia avatar mhchia commented on June 25, 2024

I guess it's because the daemon can use unix domain socket as well as the tcp socket. A multiaddress can represent both protocols.

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Nashatyrev avatar Nashatyrev commented on June 25, 2024

@mhchia The concern is not regarding the address of the daemon and not regarding the multiaddress itself but regarding its binary representation inside the Control Protocol between the daemon and a client

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vyzo avatar vyzo commented on June 25, 2024

There are multiaddrs in several other places (eg: the PeerInfo objects returned by various operations), so it felt appropriate to use the binary format.

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vyzo avatar vyzo commented on June 25, 2024

Also multiaddr is pretty well supported by the various languages and straightforward to implement for languages that don't have it yet (I had to implement for Gerbil, and it wasn't all that bad).

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mhchia avatar mhchia commented on June 25, 2024

@Nashatyrev You're right, sorry. I was writing code related to that part, so I only came up with that usage 😂 .

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