django-admin startproject project_name

patch project_name/project_name/settings.py settings.diff

Doing so will automatically update the INSTALLED_APPS and MIDDLEWARE list with custom apps and middleware NOTE:- App name and Middleware should follow this convestion

Appname:- nameApp/nameapp/name_app, should end with app/App/APP Middleware:- namemiddleware/nameMiddleware/name_middleware, should end with M/middleware also you can change then name convention latter after applying the patch, search for # change me lines You can read settings.py for the actual result of how it should be and make small changes accordingly

cp urls.py project_name/project_name/urls.py 

Doing so will automatically include the urls from the all the apps, and no need to make changes when creating new apps, It will also addes a wildcard url that will handels the 404 automatically you can change it's behaviour by modifing fOf function

cp app/urls.py project_name/app_name/urls.py

Doing so will create a urls.py file for app,which has following features:-

• SLUG variable that holds the slug for the app,eg;-SLUG='app_slug' then localhost:8000/app_slug/* will be handled by app urls.py
• view_from_class() function will create a appropirate sub_slug for each view_class in app/views.py, for view.py setup read step 5; such that localhost:8000/app_slug/sub_slug will be handled by view class in view.py direclty no need to modify urls.py again [If you are trying to use view_functions then it has no purpose you have to update the urls.py yourself]

cp app/views.py project_name/app/views.py

This view style will help you do easy modify and keep eveything under controll

class Test(View):

    """
    This class handles the :-
        url/app_slug/test
    And it's template name is
        app_slug_test
    """
    __name__ = "test"
    __slug__ = "test"

    def get(self, request):
        return HttpResponse(b"I got a get requests")