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family_db



Task 17. Определить, сколько потратил в 2005 году каждый из членов семьи

Поля в результирующей таблице:

member_name, status, costs

Используйте конструкцию "as costs" для отображения затраченной суммы членом семьи. Это необходимо для корректной проверки.

SOLUTION

select
    member_name,
    status,
    SUM(amount * unit_price) as costs
from
    Payments
    INNER JOIN FamilyMembers ON Payments.family_member = FamilyMembers.member_id
WHERE
    YEAR(date) = 2005
GROUP BY
    member_name,
    status

Task 18. Узнать, кто старше всех в семьe

Поля в результирующей таблице:

member_name

SOLUTION

SELECT member_name
FROM FamilyMembers
WHERE birthday=
    (SELECT MIN (birthday)
    FROM FamilyMembers)

Task 19. Определить, кто из членов семьи покупал картошку (potato)

Поля в результирующей таблице:

status

SOLUTION

SELECT DISTINCT status
FROM FamilyMembers
INNER JOIN Payments
    ON Payments.family_member=FamilyMembers.member_id
INNER JOIN Goods
    ON Payments.good=Goods.good_id
WHERE good_name="potato" 

Task 20. Сколько и кто из семьи потратил на развлечения (entertainment). Вывести статус в семье, имя, сумму

Поля в результирующей таблице:

status, member_name, costs

Используйте конструкцию "as costs" для отображения затраченной суммы членом семьи. Это необходимо для корректной проверки.

SOLUTION

SELECT status,
         member_name,
        (amount * unit_price) AS costs
FROM FamilyMembers
INNER JOIN Payments
    ON Payments.family_member=FamilyMembers.member_id
INNER JOIN Goods
    ON Payments.good=Goods.good_id
INNER JOIN GoodTypes
    ON GoodTypes.good_type_id=Goods.type
WHERE good_type_name="entertainment"

Task 21. Определить товары, которые покупали более 1 раза

Поля в результирующей таблице:

good_name

SOLUTION

SELECT good_name
FROM Goods
INNER JOIN Payments
    ON Payments.good=Goods.good_id
GROUP BY  Payments.good
HAVING COUNT(Payments.good)>1

Task 22. Найти имена всех матерей (mother)

Поля в результирующей таблице:

member_name

SOLUTION

SELECT member_name
FROM FamilyMembers
WHERE status='mother'

Task 23. Найдите самый дорогой деликатес (delicacies) и выведите его стоимость

Поля в результирующей таблице:

good_name, unit_price

SOLUTION

SELECT good_name,
         unit_price
FROM Payments
INNER JOIN Goods
    ON Payments.good=Goods.good_id
WHERE unit_price=
    (SELECT MAX(unit_price) AS unit_price
    FROM Payments
    INNER JOIN Goods
        ON Payments.good=Goods.good_id
    INNER JOIN GoodTypes
        ON Goods.type=GoodTypes.good_type_id
    WHERE good_type_name="delicacies")

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