junyi-99 / chatgpt-api-leakage Goto Github PK

Can you pack it into an executable file such as exe on Windows, so that it can be used directly?

I ran the script successfully but along the lines, there was an error and the script halted. I would very much like to start from the point it stopped working instead of starting from 0 again. How can I do that?
The error for reference is:
🔍 Searching ...: 35%|█████████████▉ | 182/522 [12:07:04<1081:46:41, 11454.12s/it]Traceback (most recent call last): File "/home/red/ChatGPT-API/ChatGPT-API-Leakage/main.py", line 352, in <module> main(from_iter=args.from_iter, check_existed_keys_only=args.check_existed_keys_only) File "/home/red/ChatGPT-API/ChatGPT-API-Leakage/main.py", line 321, in main leakage.search(from_iter=from_iter) File "/home/red/ChatGPT-API/ChatGPT-API-Leakage/main.py", line 217, in search self._process_url(url) File "/home/red/ChatGPT-API/ChatGPT-API-Leakage/main.py", line 124, in _process_url self.driver.get(url) File "/home/red/.local/lib/python3.10/site-packages/selenium/webdriver/remote/webdriver.py", line 356, in get self.execute(Command.GET, {"url": url}) File "/home/red/.local/lib/python3.10/site-packages/selenium/webdriver/remote/webdriver.py", line 347, in execute self.error_handler.check_response(response) File "/home/red/.local/lib/python3.10/site-packages/selenium/webdriver/remote/errorhandler.py", line 229, in check_response raise exception_class(message, screen, stacktrace) selenium.common.exceptions.TimeoutException: Message: timeout: Timed out receiving message from renderer: 288.007 (Session info: chrome=126.0.6478.61) Stacktrace: #0 0x5556c728f6aa <unknown> #1 0x5556c6f720dc <unknown> #2 0x5556c6f59456 <unknown> #3 0x5556c6f59035 <unknown> #4 0x5556c6f56f76 <unknown> #5 0x5556c6f575ef <unknown> #6 0x5556c6f67f17 <unknown> #7 0x5556c6f7e46e <unknown> #8 0x5556c6f83b6b <unknown> #9 0x5556c6f57d3a <unknown> #10 0x5556c6f7e2ee <unknown> #11 0x5556c70008f6 <unknown> #12 0x5556c6fe1613 <unknown> #13 0x5556c6fb14f7 <unknown> #14 0x5556c6fb1e4e <unknown> #15 0x5556c725587b <unknown> #16 0x5556c7259921 <unknown> #17 0x5556c724136e <unknown> #18 0x5556c725a482 <unknown> #19 0x5556c7225ccf <unknown> #20 0x5556c727f0a8 <unknown> #21 0x5556c727f280 <unknown> #22 0x5556c728e7dc <unknown> #23 0x7f050a1d2ac3 <unknown>

i get a minor bug while connecting to login page from github

Output:

> python main.py

INFO:root:Opening Chrome ...

DevTools listening on ws://127.0.0.1:51864/devtools/browser/acb03786-9b08-4e3c-9353-a9ca364cc634
INFO:root:📂 Opening database file github.db
INFO:root:🤗 No cookies found, please login to GitHub first
Press Enter after you logged in: [15640:16112:0401/120304.983:ERROR:ssl_client_socket_impl.cc(970)] handshake failed; returned -1, SSL error code 1, net_error -100
[15640:16112:0401/120304.998:ERROR:ssl_client_socket_impl.cc(970)] handshake failed; returned -1, SSL error code 1, net_error -107
[15640:16112:0401/120316.800:ERROR:ssl_client_socket_impl.cc(970)] handshake failed; returned -1, SSL error code 1, net_error -107
[15640:16112:0401/120328.677:ERROR:ssl_client_socket_impl.cc(970)] handshake failed; returned -1, SSL error code 1, net_error -107

This might be dumb cause I'm new to this, but after running the code and logging in my github account, theoretically i pressed enter, but of course it just made a new line. And I can't write a new command because the old one's still running.
$ python3 main.py
\U0001f4c2 Opening database file github.db
\U0001f30d Opening Chrome ...
\U0001f917 No cookies found, please login to GitHub first
Press Enter after you logged in:
and that's it.