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find_wday_numのコードについて

いきなりの投稿失礼いたします。
find_wday_num関数のロジックについて、連想配列を使うとスマートに書けるようになります。

def find_wday_num(str)
  wday = { "日" => 0, "月" => 1, "火" => 2, "水" => 3, "木" => 4, "金" => 5, "土" => 6 }
  return wday.has_key?(str) ? wday[str] : nil
end

こうすることで、ロジックはそのままに判定対象のデータだけを増減させることができますよ！
ご参考になれば幸いです。

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