iainnz / rationalsimplex.jl Goto Github PK
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License: MIT License
Julia implementation of the simplex algorithm for rational numbers.
License: MIT License
A problem in the current implementation: after phase 1 an artificial variable can still be in the basis (with value 0). Such variables need to be driven out of the basis before starting phase 2, otherwise they might become non-zero in phase 2, which will make the solution invalid.
This is explained here:
Drive artificial variables out of the basis: If l-th basic variable is artificial examine l-th row of B^−1 A. If all elements = 0 ⇒ row redundant. Otherwise pivot with non-0 element.
The following program demonstrates this issue. The returned solution violates the constraints:
A = [
1//1 1 0 0 0;
0 0 1 1 0;
1 0 1 0 0;
0 1 0 1 1;
0 0 0 0 1;
];
c = vec([0//1 1 1 0 0]);
b = vec([1//2 1//2 1 1 1 ]);
(status,sol) = simplex(c, A, b); # already in standard form
println(A * sol == b); # prints false, should be true
Hi and thanks for this nice module.
Is there a reason why
RationalSimplex.jl/src/RationalSimplex.jl
Line 73 in a7da62c
is not .>= zero(T)
?
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