Custom registry must have `get` function about undertaker HOT 2 CLOSED

custom registries are a very advanced feature. You probably don't want to be using them.

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@stefanstranger I ran into this error as well. I am not sure how your folder structure is setup but here is mine:

gulpfile.js
  |- gulp/
    |- default.js
    |- tasks/
      |- styles.js
      |- scripts.js
      |- clean.js

In my gulpfile.js, I have defined the HubRegistry as instructed on https://github.com/frankwallis/gulp-hub/.

var gulp        = require("gulp");
var HubRegistry = require("gulp-hub");

// Load main tasks in gulp/
var hub = new HubRegistry(["./gulp/default.js"]);

// Tell gulp to use the tasks just loaded
gulp.registry(hub);

Then in my default.js, I have

var HubRegistry = require("gulp-hub");

// Load all other gulp tasks in tasks/
var hub = new HubRegistry(["./tasks/*.js"]);

// Tell gulp to use the tasks just loaded
gulp.registry(hub);

The problem was how the Gulp tasks were being exposed in style.js or any other Gulp task file I was trying to load. At first I was using CommonJS like this and getting the same error as you:

exports.styles = styles;

So I changed those to Gulp tasks and it worked:

gulp.task("styles", styles);

FYI - I am using Gulp 4.0 so I had also installed the latest branch of gulp-hub so I'm not sure if that will make any difference. You can install it by running npm i --save-dev gulp-hub@frankwallis/gulp-hub#4.1.0.

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