jsonx-php's Introduction

JSONX for PHP

JSONx is a standard to represent JSON as XML.

You can read the documentation on IBM website.

Features

Convert any DOMNode of JSONx into PHP data that can be JSON encoded.

Install

composer require grom/jsonx

Usage

// load jsonx file ...
require_once __DIR__.'/../src/jsonx.php';

// or use composer
require 'vendor/autoload.php';

$xml = <<<XML
<?xml version="1.0" encoding="UTF-8"?>
<json:object xsi:schemaLocation="http://www.datapower.com/schemas/json jsonx.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:json="http://www.ibm.com/xmlns/prod/2009/jsonx">
    <json:boolean name="remote">false</json:boolean>
    <json:number name="height">62.4</json:number>
    <json:time name="date">2015-08-29 15:07:00</json:time>
    <json:string name="ficoScore"> > 640</json:string>
</json:object>
XML;

$dom = new \DOMDocument();
$dom->loadXML($xml);

$data = JSONx\parse($dom->documentElement);

var_dump(json_encode($data));
/*
string(69) "{"remote":false,"height":62.4,"date":1440860820,"ficoScore":" > 640"}"
 */

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jsonx-php's Issues

Convert json:object as an array

Hello,

I would like to convert json:object as an array instead of a \stdClass.

I thought I could pass a second argument to the parse function, called asArray, like this:

function parse(\DOMElement $node, $asArray = false)
{
    switch ($node->nodeName) {
        case 'json:object':
            $data = $asArray ? array() : new \stdClass();
            foreach ($node->childNodes as $childNode) {
                if ($childNode instanceof \DOMElement
                    && null !== $childNode->attributes
                    && $name = $childNode->attributes->getNamedItem('name')) {
                        if ($asArray) {
                            $data[$name->nodeValue] = parse($childNode);
                        } else {
                            $data->{$name->nodeValue} = parse($childNode);
                        }
                }
            }
            break;
// ...
}

Do you think it could be good, or do you have any other idea on this issue?

Vincent

Loosing information with json:time

Hello,

I had an issue yesterday when I ran phpunit after a fresh install.

An error occurred with the complete.test file, with the json:time field.

The issue is, that my PHP is configured with a different timezone than UTC, which causes an error when trying to convert the date specified in my timezone.

I think that globally, you should not convert a json:time to a timestamp, as you loose some information, like the timezone. You should instead return a \DateTime object, which keeps every information.

I know this change could generate a lot of work.

Vincent

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