Comments (3)
可以优化一下, 当nums[i] *3 > target 的时候直接return nums[i]+nums[i+1]+nums[i+2] 和当前closest中最接近的那个
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已添加,多谢指出~
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if (nums[i] * 3 > target) return min(closest, nums[i] + nums[i + 1] + nums[i + 2]);
should be like this:
if (nums[i] * 3 > target) {
total = nums[i] + nums[i + 1] + nums[i + 2];
if (abs(total-target) < diff) { return total;}
else{return closest}
}
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