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chapter_2, p66.c

This code does not work properly when x contains most significant bit set to 1, e.g. 0xFFFFFFFF.
Maybe this solution might avoid this problem:

  1. Main idea is to shift right and add 0x1 to set bit
  2. Save if (x == 0) to return 0 in this case: unsigned add_bit = (x == 0);
  3. After setting all right bits to 1, shift right: x >>= 1;
  4. Add bit: return (x + add_bit);

So the code will look like this:
int leftmost_one(unsigned x)
{
unsigned add_bit = (x != 0);
x |= (x >> 1);
x |= (x >> 2);
x |= (x >> 4);
x |= (x >> 8);
x |= (x >> 16);
x >>= 1;
return (x + add_bit); // Add 1 if x != 0, 0 otherwise
}

Thanks!

chapter 2, p88

Line 4 is wrong.
It should be $5 * 2^{-16}$ and $1 * 2^{-10}$

p68.c

failed for test case: lower_one_mask(32) == 0xFFFFFFFF

3.63 switch

long switch_prob(long x, long n) { long result = x; switch (n) { case 60: case 62: result = 8 * x; break; case 63: result = x >> 3; break; case 64: result = 15 * x; x = result; case 65: x *= x; default: result = x + 75; break; } return result; }

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