compilers-supplementary's Issues
Confusing new variable initialization in the Expr.lama
Here (And I guess in later tasks)
Statement:
foldl (fun (s, name) {s.addName (name, Var (0))}, state, names)
is confusing because to actually initialize a new value with 0 we have to write:
foldl (fun (s, name) {s.addName (name, 0)}, state, names)
The reason why it was not a problem is that we do not have access to the uninitialized variable in the tests. But nevertheless I guess we should rewrite it into the correct initialization with 0 or:
foldl (fun (s, name) {s.addName (name, Uninitialized)}, state, names)
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