Note
I am interested in how interpolating polynomial function by some x y point
And I found Lagrange polynomial can do that
This project started when I am in secondary school, originally written in C, and I rewrote it in C#
Note
This is part of CWKSC/MyLib_Csharp C# library, old and no longer maintain
If you include this library, its functionality is already included
There are some extension methods for printing on Demo
For example: "42".Print() == Console.Write("42"), "42".Printlnln() == Console.WriteLine("42" + "\n");
(double, double) points = { /*...*/ };
LagrangePolynomial fx = new LagrangePolynomial(points);
fx.Generate(); // return formula string
fx.Print(); // print formula // Equal to Console.Write(fx.Generate()) or fx.Generate().Print()
fx.Invoke(<x>); // input x to formula and return result (double)
// Also provide static method
LagrangePolynomial.Generate(points);
LagrangePolynomial.Print(points);
LagrangePolynomial.Invoke(<x>, points);(double, double)[] points = { (2, 7), (0, -9), (3, -3), (4, 6), (-5, 3), (1, 5), (-6, 2) };
("Generate LagrangePolynomial of " + points.ToStr()).Printlnln();
// Instance
"Using Instance Method".Printlnln();
LagrangePolynomial fx = new LagrangePolynomial(points);
"f(x) = ".Println();
fx.Generate().Printlnln();
"f(5) = ".Print();
fx.Invoke(5).Printlnlnln();
// Static Method
"Using Static Method".Printlnln();
"f(x) = ".Println();
LagrangePolynomial.Generate(points).Printlnln();
"f(5) = ".Print();
LagrangePolynomial.Invoke(5, points).Println();Generate LagrangePolynomial of (2, 7), (0, -9), (3, -3), (4, 6), (-5, 3), (1, 5), (-6, 2)
Using Instance Method
f(x) =
(7)*((x-0)/(2))*((x-3)/(-1))*((x-4)/(-2))*((x--5)/(7))*((x-1)/(1))*((x--6)/(8))+((x-2)/(-2))*(-9)*((x-3)/(-3))*((x-4)/(-4))*((x--5)/(5))*((x-1)/(-1))*((x--6)/(6))+((x-2)/(1))*((x-0)/(3))*(-3)*((x-4)/(-1))*((x--5)/(8))*((x-1)/(2))*((x--6)/(9))+((x-2)/(2))*((x-0)/(4))*((x-3)/(1))*(6)*((x--5)/(9))*((x-1)/(3))*((x--6)/(10))+((x-2)/(-7))*((x-0)/(-5))*((x-3)/(-8))*((x-4)/(-9))*(3)*((x-1)/(-6))*((x--6)/(1))+((x-2)/(-1))*((x-0)/(1))*((x-3)/(-2))*((x-4)/(-3))*((x--5)/(6))*(5)*((x--6)/(7))+((x-2)/(-8))*((x-0)/(-6))*((x-3)/(-9))*((x-4)/(-10))*((x--5)/(-1))*((x-1)/(-7))*(2)
f(5) = 121.34126984126983
Using Static Method
f(x) =
(7)*((x-0)/(2))*((x-3)/(-1))*((x-4)/(-2))*((x--5)/(7))*((x-1)/(1))*((x--6)/(8))+((x-2)/(-2))*(-9)*((x-3)/(-3))*((x-4)/(-4))*((x--5)/(5))*((x-1)/(-1))*((x--6)/(6))+((x-2)/(1))*((x-0)/(3))*(-3)*((x-4)/(-1))*((x--5)/(8))*((x-1)/(2))*((x--6)/(9))+((x-2)/(2))*((x-0)/(4))*((x-3)/(1))*(6)*((x--5)/(9))*((x-1)/(3))*((x--6)/(10))+((x-2)/(-7))*((x-0)/(-5))*((x-3)/(-8))*((x-4)/(-9))*(3)*((x-1)/(-6))*((x--6)/(1))+((x-2)/(-1))*((x-0)/(1))*((x-3)/(-2))*((x-4)/(-3))*((x--5)/(6))*(5)*((x--6)/(7))+((x-2)/(-8))*((x-0)/(-6))*((x-3)/(-9))*((x-4)/(-10))*((x--5)/(-1))*((x-1)/(-7))*(2)
f(5) = 121.34126984126983
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