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License: Apache License 2.0
mmseg4j core MMSEG for java chinese analyzer
License: Apache License 2.0
com.chenlb.mmseg4j.Dictionary的静态方法getInstance没有添加synchronized方法,导致多线程访问时达不到单例的效果,最终导致了一个文件系统的异常。
如题,在实际应用中可能会出现分词的时候使用max-word,而检索采用complex,但您的max-word测试后发现是最多两个字一组,这样的话是否有问题?我在使用的过程中是将其能分成更多的词,比如 计算机学院 我会分成 计算机、学院、计算 这样的,我对代码修改了一点,其中主要对MaxWordSeg.java进行了修改,如下:
public Chunk seg(Sentence sen) {
Chunk chunk = new Chunk();
char[] chs = sen.getText();
List<Word> cks = new ArrayList<Word>();
for(int k=0; k<3&&!sen.isFinish(); k++) {
int offset = sen.getOffset();
int maxLen = 0;
//有了 key tree 的支持可以从头开始 max match
ArrayList<Integer> lens = dic.maxMatchs(chs, offset);
maxLen = lens.get(0);
for(int len:lens){
if(len>maxLen){
maxLen = len;
}
cks.add(new Word(chs, sen.getStartOffset(), offset, len+1));
}
chunk.words[k] = new Word(chs, sen.getStartOffset(), offset, maxLen+1);
offset += maxLen + 1;
sen.setOffset(offset);
}
chunk.words = cks.toArray(new Word[cks.size()]);
chunk.count = cks.size();
return chunk;
}
如有不当之处,请见谅
java.util.ConcurrentModificationException: null
at java.util.ArrayList$Itr.checkForComodification(ArrayList.java:859) ~[na:1.7.0_75]
at java.util.ArrayList$Itr.next(ArrayList.java:831) ~[na:1.7.0_75]
at com.chenlb.mmseg4j.rule.Rule.remainChunks(Rule.java:39) ~[na:na]
at com.chenlb.mmseg4j.ComplexSeg.seg(ComplexSeg.java:102) ~[na:na]
at com.chenlb.mmseg4j.MMSeg.next(MMSeg.java:179) ~[na:na]
由于com.chenlb.mmseg4j.rule.Rule类中chunks变量,在遍历这个对象的时候,有增加和删除操作会出现该异常。
请参考http://www.cnblogs.com/dolphin0520/p/3933551.html
谢谢
比如,我想把”奥迪A1“做为一个词,写在了自定义词典里,分词之后,我期望的结果是“奥迪A1”,但是得到的是“奥迪|A1”
在IK的分词器里也是这样。
请问,我写在自定义词典里的词,如何分到一个词?
why default seg letter and digit together ? How can I set to split them ?
Maybe they should be splitted.
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