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Solutions to problems from various online judges / contest sites.

License: Do What The F*ck You Want To Public License

Python 15.17% C++ 74.37% Common Lisp 2.96% OCaml 0.96% Ruby 0.34% Rust 0.35% Nim 1.72% C 0.14% Shell 0.05% Brainfuck 0.03% Dylan 1.08% Dockerfile 0.30% D 0.10% Standard ML 0.14% Haxe 0.33% MoonScript 0.10% Pony 0.24% Racket 1.01% Julia 0.33% Factor 0.27%
competitive-programming solutions kattis kattis-solutions atcoder atcoder-solutions hackerrank hackerrank-solutions hackerearth hackerearth-solutions

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competitive-programming's Issues

/cses/1081.cc

I submitted the same solution you provided but it gives time limit exceeded
please recheck the solution of Common Divisors

Help wanted

CAn you please explain why this matrix was constructed in such a way

for (int i = 0; i < 5; i++) a[i][i+1] = 1;

I know that later part will be solved by matrix exponentiation. But facing some difficulties in building the base matrix

greetingcard.cc

I have a very similar Pythonic solution to greeting card (https://open.kattis.com/problems/greetingcard) by hardcoding the only possible situations where pairs of points are exactly 2018 units apart. However, my solution failed with a "TLE" message failing on the 5/11 test case and I just couldn't figure out why.

Is your solution able to successful pass all the test cases on Kattis?

T = int(input())

lattice = []
for _ in range(T):
    x, y = map(int, input().split())
    lattice.append((x, y))

count = 0
for index in range(len(lattice)):
    cur_x = lattice[index][0] 
    cur_y = lattice[index][1]
    for jndex in range(index, len(lattice)):
        
        nex_x = lattice[jndex][0]
        nex_y = lattice[jndex][1]
        
        if ((cur_x + 2018 == nex_x and cur_y == nex_y) or
        (cur_x - 2018 == nex_x and cur_y == nex_y) or
        (cur_x == nex_x and cur_y + 2018 == nex_y) or
        (cur_x == nex_x and cur_y - 2018 == nex_y) or
        # more
        (cur_x + 1118 == nex_x and cur_y + 1680 == nex_y) or
        (cur_x + 1118 == nex_x and cur_y - 1680 == nex_y) or
        (cur_x - 1118 == nex_x and cur_y + 1680 == nex_y) or
        (cur_x - 1118 == nex_x and cur_y - 1680 == nex_y) or
        # more
        (cur_x + 1680 == nex_x and cur_y + 1118 == nex_y) or
        (cur_x + 1680 == nex_x and cur_y - 1118 == nex_y) or
        (cur_x - 1680 == nex_x and cur_y + 1118 == nex_y) or
        (cur_x - 1680 == nex_x and cur_y - 1118 == nex_y)):
            count += 1
print(count)

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