实际测试发现AT24C02无法正常写入EEPROM about at24cxx HOT 2 CLOSED

在测试发现AT24C02无法正常写入EEPROM，只能正确写入几个不连续的字节，查看代码发现在写入成功的时候没有延时如下所示 rt_err_t at24cxx_write(at24cxx_device_t dev, uint32_t WriteAddr, uint8_t *pBuffer, uint16_t NumToWrite) { uint16_t i = 0; rt_err_t result; RT_ASSERT(dev);

if(WriteAddr + NumToWrite > AT24CXX_MAX_MEM_ADDRESS)
{
    return RT_ERROR;
}

result = rt_mutex_take(dev->lock, RT_WAITING_FOREVER);
if (result == RT_EOK)
{
    while (1) //NumToWrite--
    {
        if (at24cxx_write_one_byte(dev, WriteAddr, pBuffer[i]) != RT_EOK)
        {
            rt_thread_mdelay(EE_TWR);
        }
        else
        {
            WriteAddr++;
            i++;
        }
        if (i == NumToWrite)
        {
            break;
        }

    }
}
else
{
    LOG_E("The at24cxx could not respond  at this time. Please try again");
}
rt_mutex_release(dev->lock);

return RT_EOK;

}

将这个函数改成下面即可成功写入 rt_err_t at24cxx_write(at24cxx_device_t dev, uint32_t WriteAddr, uint8_t *pBuffer, uint16_t NumToWrite) { uint16_t i = 0; rt_err_t result; RT_ASSERT(dev);

if(WriteAddr + NumToWrite > AT24CXX_MAX_MEM_ADDRESS)
{
    return RT_ERROR;
}

result = rt_mutex_take(dev->lock, RT_WAITING_FOREVER);
if (result == RT_EOK)
{
    while (1) //NumToWrite--
    {
        if (at24cxx_write_one_byte(dev, WriteAddr, pBuffer[i]) == RT_EOK)
        {
            WriteAddr++;
        }
        if (++i == NumToWrite)
        {
            break;
        }
        rt_thread_mdelay(EE_TWR);
    }
}
else
{
    LOG_E("The at24cxx could not respond  at this time. Please try again");
}
rt_mutex_release(dev->lock);

return RT_EOK;

}

目前问题依旧，用at24cxx write 后读出只有第一个字节，改为你的每个都延迟后正常。

from at24cxx.

谢谢

from at24cxx.