Comments (5)
Yes.
You can try:
import * as express from "express";
import {Server} from "typescript-rest";
import {ServiceOne} from "./service-one";
import {ServiceTwo} from "./service-two";
import {ServiceThree} from "./service-three";
let app: express.Application = express();
Server.buildServices(app, ServiceOne, ServiceTwo, ServiceThree);
And write your @ ROUTES in each of those files, like:
import {Server, Path, GET, PathParam} from "typescript-rest";
@Path("/hello")
export class ServiceOne {
}
from typescript-rest.
oops! i understand. thank you very match.
from typescript-rest.
If you have many services distributed in many modules, you can also join all of them and re-export, to facilitate the maintenance of the code:
import {StatsRest} from "./stats";
import {MiddlewareRest} from "./middleware";
import {APIRest} from "./api";
import {HealthCheck} from "./health-check";
import {UsersRest} from "./users";
import {GatewayRest} from "./gateway";
export default [StatsRest, MiddlewareRest, APIRest, HealthCheck, UsersRest, GatewayRest];
and then, on your main file:
import adminApi from "./admin-apis";
const app = express();
Server.buildServices(app, ...adminApi);
Or you can also call Server.buildServices
multiple times, with different classes to register.
import adminApi from "./admin-apis";
import {ServiceOne} from "./service-one";
const app = express();
Server.buildServices(app, ...adminApi);
Server.buildServices(app, ServiceOne);
from typescript-rest.
Nice! It works.
from typescript-rest.
I created a new issue (#24), proposing a better approach to this.
from typescript-rest.
Related Issues (20)
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from typescript-rest.