Comments (2)
真太阳时只和经度有关,与纬度无关
此问题有两种计算方法
-
从真平太阳时定义上看:真太阳时=当地平太阳时+均时差
当地平太阳时可以通过给时间、时区和经度算出,均时差通过公式也能得到,两者相加即为当地朕太阳时 -
另一方面,天文意义上看,真太阳时就是太阳的天球位置与子午线的夹角,即太阳时角(日晷影)
太阳上中天时,太阳时角为0度,对应的真太阳时为12时,也就是真太阳时=太阳时角+12小时
两种方法对应的代码如下
package main
import (
"fmt"
"github.com/starainrt/astro/basic"
"github.com/starainrt/astro/sun"
"math"
"time"
)
func main() {
cst := time.FixedZone("CST", 8*3600)
date := time.Date(2022, 1, 1, 0, 0, 0, 0, cst)
fmt.Println(date, "\n",
ApparentSolarTime(date, 115), "\n",
ApparentSolarTime2(date, 115))
}
// 方法一:真太阳时=当地平太阳时+均时差
func ApparentSolarTime(date time.Time, lon float64) time.Time {
//取世界时,用于计算均时差
jde := basic.Date2JDE(date.UTC())
LocalTimezone := int(lon * 3600.00 / 15.0)
//pTime:获取当地经度时区的平太阳时
pTime := date.In(time.FixedZone("LTZ", LocalTimezone))
//真太阳时=平太阳时+均时差
return pTime.Add(time.Duration(basic.SunTime(jde) * 3600 * 1000 * 1000 * 1000))
}
// 方法二 真太阳时=太阳时角+12小时
func ApparentSolarTime2(date time.Time, lon float64) time.Time {
//真太阳时=太阳时角+12小时
trueTime := (sun.HourAngle(date, lon, 0) + 180) / 15
if trueTime > 24 {
trueTime -= 24
}
//真太阳时的分
minute := (trueTime - math.Floor(trueTime)) * 60
//真太阳时的秒
second := (minute - math.Floor(minute)) * 60
//当地经度下的本地时区
trueSunTime := date.In(time.FixedZone("LTZ", int(lon*3600.00/15.0)))
if trueSunTime.Hour()-int(trueTime) > 12 {
trueSunTime = trueSunTime.Add(time.Hour * 24)
} else if int(trueTime)-trueSunTime.Hour() > 12 {
trueSunTime = trueSunTime.Add(-time.Hour * 24)
}
return time.Date(trueSunTime.Year(), trueSunTime.Month(), trueSunTime.Day(),
int(trueTime), int(minute), int(second), int((second-math.Floor(second))*1000000000),
time.FixedZone("LTZ", int(lon*3600.00/15.0)))
}
运行结果如下:
2022-01-01 00:00:00 +0800 CST //北京时间
2021-12-31 23:36:51.633708344 +0740 LTZ //当地真太阳时 方法一
2021-12-31 23:36:51.373404123 +0740 LTZ //当地真太阳时 方法二
两个方法0.3秒的差异在于迭代次数的不同,方法二的精度会更高,但是速度会更慢。
计算结果的时区均为当地经度时区,非传入时的标准时区
from astro.
多谢 选择第二个了
from astro.
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from astro.