Should For.yield not return a Stream instead of a List? about soabase-halva HOT 6 CLOSED

I think, instead, there should be a stream() method or something to allow continuing the stream. yield() in Scala is a terminal.

from soabase-halva.

Oh you're totally right, I'm mixing up Haskell do and Scala for, d'oh :)

from soabase-halva.

Hmmm, are you sure yield is a terminal operation?

Eg http://docs.scala-lang.org/tutorials/FAQ/yield.html

    for(x <- c1; y <- c2; z <- c3) yield {...}
//===
    c1.flatMap(x => c2.flatMap(y => c3.map(z => {...})))

so if c1 is a stream then the for comprehension would also be a stream, no?

from soabase-halva.

Scala doesn't have an analog to stream() right? You can directly map any sequence. I don't think there's a way to do this in Java without introducing a stream() method to For - which I think is a good idea actually.

from soabase-halva.

So, with Halva, you'd end up with:

forComp(l, myList)
    .forComp(y, l.whatever)
    .stream(() -> i + y)    // stream() instead of yield
    .map(x -> x * 10)     // here we're out of forComp into JDK-land

from soabase-halva.

stream() method added.

from soabase-halva.