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Comments (2)

santoshrajan avatar santoshrajan commented on June 17, 2024

You cannot 'require' lispyscript like that. You have to run it from the command line. see docs.

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leizongmin avatar leizongmin commented on June 17, 2024

I want to use lispyscript like this without compile command:

require('./mycode.ls');

Now the problem has been solved:

var path = require('path');
require(path.resolve(path.dirname(require.resolve('lispyscript')), 'node.js'));
require('lispyscript');

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