MethodBinderWithArgument のInvoke()で、引数を定義型のサブクラスにすると呼び出しに失敗する about livet HOT 5 CLOSED

if (parameters[0].ParameterType.IsInterface)
{
    if (!newArgumentType.GetInterfaces().Contains(parameters[0].ParameterType)) return false;
}
else
{
    if ((!_argumentType.IsSubclassOf(parameters[0].ParameterType)) && (_argumentType != parameters[0].ParameterType)) return false;
}

class Program
{
    static void Main(string[] args)
    {
        TestNormal();
        TestBinder();
    }

    private static void TestNormal()
    {
        // MethodBinderWithArgument を使わない通常の呼び出し
        Super calleeArg = null;
        var test = new Test(x => calleeArg = x);
        var callerArg = new Sub();
        test.TestMethod(callerArg);
        Console.WriteLine(callerArg == calleeArg);  // True
        test.TestMethod2(new Other());
    }

    private static void TestBinder()
    {
        // MethodBinderWithArgument を使った呼び出し
        Super calleeArg = null;
        var test = new Test(x => calleeArg = x);
        var binder = new MethodBinderWithArgument();
        var callerArg = new Sub();
        binder.Invoke(test, "TestMethod", callerArg);    // ArgumentException となる
        Console.WriteLine(callerArg == calleeArg);
        binder.Invoke(test,"TestMethod2",new Other());
    }
}

interface TestInterface
{

}

class Test
{
    private readonly Action<Super> action;

    public Test(Action<Super> action)
    {
        this.action = action;
    }

    public void TestMethod(Super arg) => this.action?.Invoke(arg);
    public void TestMethod2(TestInterface t) => this.action?.Invoke(null);
}
class Super { }
class Sub : Super { }
class Other : TestInterface { }