Comments (5)
Идея:
class ASchema(Schena):
def pre_parse(self, data):...
class BSchema(ASchema):
def pre_parse(self, data):
data = super().pre_parse(data)
...
проверить, что такое допустимо и работает
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Идея. Предположим меня есть два базовых датакласса и есть у них схемы, описывающие правила парсинга (какие поля парсить, предобработка и т.п.)
@dataclass
class A:
a: int
x: str = None
@dataclass
class B:
b: int = 0
y: str = None
class ASchema(Schema):
only = ["a"]
name_style = NameStyle.snake
def pre_parse(self, data):
print("aschema")
data["a"] = data["a"] * 2
return data
class BSchema(Schema):
only = ["b"]
exclude = ["y"]
def pre_parse(self, data):
print("bschema")
data["b"] = -data["b"]
return data
aschema = ASchema()
bschema = BSchema()
Если я наследую от них обоих новый датакласс, для него никакая схема применяться не будет.
Насколько логично иметь такой алгоритм:
- pre_parse/post_parse/pre_serialize/post_serialize вызываются в MRO порядке
- only, exclude, name_mapping объединяются в MRO порядке
- прочие настройки типа name_style проверяются чтобы не противоречили друг другу.
- кастомные parse, serialize не должны быть заданы
То есть в данном случае будет эквивалентно:
@dataclass
class C(A, B):
pass
def c_pre_parse(self, data):
data = aschema.pre_parse(self, data)
data = bschema.pre_parse(self, data)
return data
cschema = Schema(
only = ["a", "b"],
exclude = ["y"],
name_style = NameStyle.snake,
pre_parse = c_pre_parse,
)
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Вопрос: как быть в случае когда один класс наследуется от другого, а там определен только only
from adaptix.
Вопрос: что если два родительских класса с разными стилями имён?
Имеет смысл поддержать чтобы их поля оба парсились корректно
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This issue is not actual with the new major version
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