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hugovk avatar hugovk commented on June 12, 2024 1

Looks like a duplicate of #88536.

If math.nan is the first argument for either max() or min(), the result is always nan, regardless of the other values in the results. However, if nan is in any other position in the arguments list, the result is always what you would expect if nan was not in the arguments list.
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Eclips4 avatar Eclips4 commented on June 12, 2024

NAN per definition does equal itself, so this is the test for nan without functions. Same for other compares.

IEEE-754 says the opposite:

Any comparison with a NaN is treated as unordered.

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alex77g2 avatar alex77g2 commented on June 12, 2024

yes, but this is not obvious to each python user. and python is intended to be as friendly or comfortable or easy to understand as possible. No hint in documentation?

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Eclips4 avatar Eclips4 commented on June 12, 2024

yes, but this is not obvious to each python user. and python is intended to be as friendly or comfortable or easy to understand as possible. No hint in documentation?

There's already a hint in documentation: https://docs.python.org/3/library/math.html#math.nan:

Due to the requirements of the IEEE-754 standard, math.nan and float('nan') are not considered to equal to any other numeric value, including themselves.

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alex77g2 avatar alex77g2 commented on June 12, 2024

I mean a hint in max(), min() docu. As not everybody ready everything. I assume many users dont even know about NAN.

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Eclips4 avatar Eclips4 commented on June 12, 2024

I mean a hint in max(), min() docu. As not everybody ready everything. I assume many users dont even know about NAN.

This behaviour currently is under discussion, please read the issue found by Hugo.

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