Comments (2)
Hi @NikkyAI please see #14 (comment). According to GraphQL specification mutation type is optional, but unfortunately Graphiql does not comply to specification in this matter.
Your solution is right now the best workaround for this problem.
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got it to work by registering a dummy mutation that does nothing
mutation("doNothing") {
description = "Does nothing"
resolver { a: String ->
LOG.info("called mutation with $a")
Dummy()
}
}
type<Dummy> ()
from kgraphql.
Related Issues (20)
- Extension property not working HOT 1
- Support for suspendable property resolvers HOT 2
- There is no instruction to help a new user to start the server and the client in this example. How can I run the server and start query? HOT 2
- LocalDate coercion issue HOT 2
- Support for suspendable schema execution HOT 1
- Property resolver with context HOT 8
- Scalar types within variables not working HOT 1
- How would I handle query/mutation authentication? HOT 4
- Print Schema? HOT 1
- Adding Context parameter to resolver causes errors in introspection HOT 3
- Fragments not resolving correctly on same data node
- Nested Fragments fail with property does not exist HOT 2
- LocalDate when passed as query variable HOT 1
- Leaking top level
- Is this the right way with using resolvers on a type? HOT 2
- Support for suspendable unionProperty resolvers
- Implement a DataLoaderDSL for batching
- Caused by: java.lang.NoClassDefFoundError: kotlinx/coroutines/experimental/CommonPool HOT 1
- When overwriting a property, the GraphQL repeats the original property unless ignored
- release 0.3.1 build? HOT 2
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