Comments (2)
pezy
commented on May 22, 2024
为什么第一段代码中，bq,lq的两个属性没有输出？
因为都是 r 调用 debug， 而 r 是 Quote.
为什么第三段代码中，q会输出他没有的两个属性的值？
麻烦认真点， 第三段里调用 debug 输出的是 r4, 这里发生了动态绑定，r4 实际是 Limit_quote.
为什么第四段代码中，r5会输出lq的值？
当然啦， 你把 lq 赋值给 r， r 就是 q，r5 也就是 q， r5 输出的值当然就是 lq 的值。
为什么会这样，还请麻烦解释一下，谢谢！！！
为什么会这样， 好好看书就明白了!!!
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susong
commented on May 22, 2024
谢谢您的解答，果然是我看书不够细心，麻烦您了，谢谢！！！
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