/catch-the-xmlhttp-request-in-plain-javascript/ about dmitripavlutin.com-comments HOT 13 OPEN

Comment written by Martin Spierings on 06/21/2017 10:16:14

While you catch the code, this doesn't really prevent further execution

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Comment written by Tánh Lee on 12/14/2017 02:33:52

Thank you very much!! You saved my life <3 Subscribing your blog from today

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Comment written by Alex Nevi on 02/21/2018 02:54:18

But you can prevent sending.

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Comment written by Alex Nevi on 02/21/2018 03:11:19

Пасяп, бр0!
Dunno why, but
if(this._onreadystatechange){
not work, replace it with
if(this.readyState === 4){
and comment return this._onreadystatechange.apply(this, arguments);
in my UserScript.
https://developer.mozilla.o...

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Comment written by loopmode on 05/15/2018 06:48:34

Hi. Nice approach.

Is there a particular reason you guard against missing onreadystatechange?
If not, we should just leave the if(this.onreadystatechange) and if(this._onreadystatechange) checks away.

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Comment written by bvp on 04/09/2019 06:11:10

In my case ajax request are originating from vendor specific js file. But in my application I have added your script on the top of all the JavaScript files.But then also this script is not working and even not entering in any of the openreplacement and endreplacement functions. Do we need to start ajax call from the same script scope ?.

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Comment written by Dmitri Pavlutin on 04/09/2019 06:35:00

If the vendor specific JS code is executed in the same scope as your script, it should work fine.

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Comment written by bvp on 04/09/2019 06:49:13

From my vendor js file, 8 ajax calls are originating. What my requirement is to run my custom function after finishing all the ajax calls. So I want to know when the ajax calls are finished.

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Comment written by bvp on 04/09/2019 09:48:18

When I checked the code, I found that these are not writable. XMLHttpRequest.prototype.open and XMLHttpRequest.prototype.send
What should I do to make it writable ?

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Comment written by exetico on 05/14/2019 18:12:03

Where have you added the code? I've tried to execute it within a JS-file, added in content_scripts > js, but it doesn't work. Should it be added to the original window, or how? :-)

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Comment written by Dmitri Pavlutin on 05/19/2019 09:15:53

Most likely you need to add the JavaScript directly into the original window context.

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Very interesting. Can I then bypass it in a subsequent code as:

function openReplacementBypass(XMLHttpRequestOBJ,method, url, async, user, password)
{
var open = XMLHttpRequestOBJ.prototype.open;
return open(method, url, async, user, password);
}

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Let me ask a question about something related. If I execute a function native from the webpage I'm monitoring and I know it will end up in a XHR request for which I know the URL, how would I capture the response body of that XHR request?

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