request for adios_long_long, adios_cxx_bool about adios HOT 3 CLOSED

Hi Andrew,

ADIOS types are fixed size, they don't depend on compiler settings. So I
don't know how to support bool type with who knows what size.

On the other hand, adios_long is defined as 8 bytes integer (handled as
int64_t), so if you see it behaves differently, that's a bug.

Best regards
Norbert

On Fri, Oct 4, 2013 at 3:19 PM, Andrew Corrigan [email protected]:

First of all: Sorry for all the nitpicking! ADIOS is awesome, these are
just some minor issues that it would be nice to have resolved :)

Is it possible to define adios_long_long and adios_cxx_bool?

I see that there is adios_long, but adios_long is not necessarily
guaranteed to be 64-bit, and therefore my code uses 'long long', instead.
Currently I have a runtime check that sizeof(long) == sizeof(long long), in
order to process 'long long' data with ADIOS, but there is no guarantee of
this.

Likewise, I am currently working around the lack of adios_cxx_bool (as is
available in the latest MPI) by using adios_byte, but I do not believe that
there is any guarantee that bool is just 1 byte.

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from adios.

I apologize for my misunderstanding, and thank you for the clarification.

Just to be sure I understand correctly now, I see in adios_types.h there are comments with sizes. I assume therefore that if I am on a machine where sizeof(long) == 4, I would not use adios_long (i.e. 8 bytes), and instead use adios_integer (i.e. 4 bytes), correct?

I understand that I am being pedantic, I just want to get this right in my code once and for all, and forget about it.

from adios.

Yes, that's right. And you are not pedantic. If you used a type with 4
bytes long and let ADIOS believe you have a type with 8 bytes that would
result in invalid memory accesses.

On Fri, Oct 4, 2013 at 6:00 PM, Andrew Corrigan [email protected]:

I apologize for my misunderstanding, and thank you for the clarification.

Just to be sure I understand correctly now, I see in adios_types.h there
are comments with sizes. I assume therefore that if I am on a machine where
sizeof(long) == 4, I would not use adios_long (i.e. 8 bytes), and
instead use adios_integer (i.e. 4 bytes), correct?

I understand that I am being pedantic, I just want to get this right in my
code once and for all, and forget about it.

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Reply to this email directly or view it on GitHubhttps://github.com//issues/11#issuecomment-25733009
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