JSON and HTML reports are not generated if a directory is given to --json and --html options about fastp HOT 4 CLOSED

For the archive; to answer my own question:
after 2nd thought the solution was quite simple: before calling fastp I only had to add a command to create a new directory:
mkdir -p $PWD/fastp_out/${fn}
That was all....

from fastp.

But actually this can be done with --json <dir/fastp.json> --html <dir/fastp.html>.

fastp will throw an error and quit immediately if you specify a existing folder name directly.

from fastp.

Yes yes of course, it was just an idea!

By default names were ok for me so I just try to give a directory to these 2 options and it did not work.

Thanks for your answer!

from fastp.

Likely a stupid question, but since I am struggling with something similar:

How to generate a report if I am using for <dir> a character string that is composed of a directory name + fastq name? Thus e.g. 'samplenumber/fastqname'?

My file setup:

workingdir
    seqdata
        - sample1
            --file1.fq.gz
        - sample 2
            --file2.fq.gz


    pfast_out

In the working directory I am executing fastp in a loop using:

#!/bin/bash
find $PWD/seqdata \( -name '*.fq.gz' -or -name '*.fq' \) -print0 | while read -d $'\0' fn
do
echo "Processing sample ${fn}"
fastp -i ${fn} -p -w 4  --json $PWD/pfast_out/${fn}/fastp.json --html $PWD/pfast_out/${fn}/fastp.html
done

The directory pfast_out (in workingdir) is created by me before starting pfast, but the *.json and *.html files are not generated??

Output names are: /workingdir/pfast_out/seqdata/sample1/file1.fq.gz/fastp.json, etc.

I think that since the sub-directory in bold doesn't exists when the files have to be written, the*.json and *.html files are not generated...
How to achieve this?

Thanks for any suggestions!

from fastp.