Comments (2)
I don't know. Used help only to show subcomands list. It's better to search in google for python's examples.
from argparse.
Find a working python example, then it should work here as well.
Something like this?:
https://stackoverflow.com/questions/20094215/argparse-subparser-monolithic-help-output
#!/usr/bin/env node
'use strict';
let argparse = require('./')
// create the top-level parser
let parser = argparse.ArgumentParser('PROG')
parser.add_argument('--foo',{ action: 'store_true', help: 'foo help' })
let subparsers = parser.add_subparsers({help: 'sub-command help'})
// create the parser for the "a" command
let parser_a = subparsers.add_parser('a', {help: 'a help'})
parser_a.add_argument('bar',{ type: 'int', help: 'bar help'})
// create the parser for the "b" command
let parser_b = subparsers.add_parser('b', {help: 'b help'})
parser_b.add_argument('--baz', {choices: 'XYZ', help: 'baz help'})
// print main help
console.log(parser.format_help())
// retrieve subparsers from parser
let subparsers_actions = parser._actions
.filter(a => a.constructor.name === '_SubParsersAction')
// there will probably only be one subparser_action,
// but better safe than sorry
for (let subparsers_action of subparsers_actions) {
// get all subparsers and print help
for (let [ choice, subparser ] of Object.entries(subparsers_action.choices)) {
console.log(`Subparser '${choice}'`)
console.log(subparser.format_help())
}
}
This is the example from that SO article ported to js.
You can override ArgumentParser.print_help() via subclass to print it.
from argparse.
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from argparse.