Can distcc handle script dependency during compilation? about distcc HOT 5 CLOSED

Distcc can handle that fine.

There's two ways to handle it using distcc.
The recommended approach is to use

   make CC="distcc gcc"

and for your Makefile to refer to $(CC) rather than gcc.
However, if you have existing scripts or Makefiles that have "gcc" hard-coded, 
and
you don't want to change them, there's a solution for that too.
You can use "masquerading".  See the "MASQUERADING" section of the distcc man 
page.
http://distcc.googlecode.com/svn/trunk/doc/web/man/distcc_1.html#TOC_11

Thanks, but I know the usage CC=distcc~.
The question that I did is 

'may scripts can make dependencies with other compilation commands'

Here is some pseudo code:

1 : if distcc a.c then change variable BVAR of b.c to -1 else BVAR=1
2 : distcc c.c
3 : distcc b.c

If distcc launches those three commands in simultaneously, then 3rd compilaiton
job cannot guarantee its correctness.
How distcc handle the dependency problem?

Dependency checking is handled by "make".
If you declare the dependencies in your makefile so that
  make -j
works correctly, then
  make -j CC=distcc
should work fine too.
Use of distcc makes no difference to how you should declare the dependencies in 
you makefile.

Dependency checking is handled by "make".
If you declare the dependencies in your makefile so that
  make -j
works correctly, then
  make -j CC=distcc
should work fine too.
Use of distcc makes no difference to how you should declare the dependencies in 
you makefile.

Dependency checking is handled by "make".
If you declare the dependencies in your makefile so that
  make -j
works correctly, then
  make -j CC=distcc
should work fine too.
Use of distcc makes no difference to how you should declare the dependencies in 
you makefile.