What's the PDE problem for Poisson_periodic_1d.py ? about deepxde HOT 4 CLOSED

It is Poisson equation: -du_xx = np.pi ** 2 * sin(np.pi * x) on 1D domain [-1, 1]. There are two BCs:

• Dirichlet u(-1) = sin(-np.pi)
• Periodic u(1) = u(-1).

If you want to use high order derivative periodic du/dx(-1) = du/dx(1),

bc = dde.PeriodicBC(geom, 0, boundary_r, derivative_order=1)

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Thanks !

from deepxde.

It is Poisson equation: -du_xx = np.pi ** 2 * sin(np.pi * x) on 1D domain [-1, 1]. There are two BCs:

• Dirichlet u(-1) = sin(-np.pi)
• Periodic u(1) = u(-1).

If you want to use high order derivative periodic du/dx(-1) = du/dx(1),

bc = dde.PeriodicBC(geom, 0, boundary_r, derivative_order=1)

Hi Lu, I'd like to understand about periodicBC. What's mean about component_x? It refers to the independent variable, here it refers to x？
If the following equation satisfies the periodic boundary conditions, then is the periodic boundary set like this？
equation: ut-utxx+4uux-3uxuxx-u*uxxx=0

bc_u = dde.PeriodicBC(geomtime, 0, lambda _, on_boundary: on_boundary）

from deepxde.

component_x is the component of inputs to be periodic. component_x=0 is periodic in x; component_x=1 is periodic in y.

What you wrote is correct.

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