Comments (2)
I was curious if this might be related (or not)...
(defn take-none [f]
(m/eduction (take 0) f))
(defn echo [f]
(m/ap
(let [v (m/?> f)]
(prn 'produce v)
v)))
(m/?
(m/reduce (fn [_ _]) nil
(take-none (echo (m/seed (range))))))
produce 0
produce 1
The echo/seed combination gets two values ahead of the consumer before being cancelled.
Now let's add in another layer:
(defn copy [f]
(m/ap (m/?> f)))
... (take-none (copy (echo (m/seed (range)))))
produce 0
produce 1
produce 2
... (take-none (copy (copy (echo (m/seed (range))))))
produce 0
produce 1
produce 2
produce 3
Each added copy
buffers an additional value, so each copy
we add causes the producer to get an additional value ahead of the consumer.
Suppose this issue was implemented. In copy
, the branch doesn't contain an asynchronous operator (it doesn't do anything but return), so the continuation would be evaluated lazily... and would that mean that copy
would no longer buffer an additional value in a pipeline like it does now?
from missionary.
yes, when this issue is solved copy
will be semantically equivalent to identity
.
from missionary.
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from missionary.