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Comments (5)

sniffdk avatar sniffdk commented on August 16, 2024

Try this:

return View(tweetUrl, item);

from leblender.

kipusoep avatar kipusoep commented on August 16, 2024

Thanks @sniffdk, your suggestion got me thinking:

public class TwitterController : LeBlenderController
{
    public ActionResult Index(LeBlenderModel model)
    {
        var item = model.Items.Single();
        string tweetUrl = item.GetValue<string>("tweetURL");
        return View((object)tweetUrl);
    }
}

from leblender.

sniffdk avatar sniffdk commented on August 16, 2024

Awesome 😃

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tajamal avatar tajamal commented on August 16, 2024

Hi @kipusoep and @sniffdk

I am looking for a similar solution but i am not hitting Index ActionResult, what do i need to do ?

public class ProfileEditLoginController : LeBlenderController
    {
        // GET: ProfileEditLogin
        public ActionResult Index(LeBlenderModel model)
        {

            return View(new ProfileEditLoginView());
        }
}

from leblender.

tajamal avatar tajamal commented on August 16, 2024

And instead thrown this error message

The model item passed into the dictionary is of type 'Lecoati.LeBlender.Extension.Models.LeBlenderModel', but this dictionary requires a model item of type 'MyProject.Models.Profile.ProfileEditLoginView'.

from leblender.

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