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JangoSteve avatar JangoSteve commented on August 20, 2024

I'm a little unclear on what the use-case is. It seems like this would only happen if there are zero tabs total in the easytab container. If that's the case though, could you avoid calling easytabs in some way (maybe by only calling it on a selector that exists if there is at least one tab present)?

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MobsterGit avatar MobsterGit commented on August 20, 2024

Thanks for the reply. I think resolved it with a little if statement, if easytabs, do something. If you want, I'll post it as a follow up in case someone else runs into the issue.

~Denny

Sent from my iPhone

On Dec 17, 2015, at 12:10 PM, Steve Schwartz [email protected] wrote:

I'm a little unclear on what the use-case is. It seems like this would only happen if there are zero tabs total in the easytab container. If that's the case though, could you avoid calling easytabs in some way (maybe by only calling it on a selector that exists if there is at least one tab present)?


Reply to this email directly or view it on GitHub.

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JangoSteve avatar JangoSteve commented on August 20, 2024

Awesome, thanks, that'd be great.

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MobsterGit avatar MobsterGit commented on August 20, 2024

Ok, so I resolved this by including it in an "if" conditional to see if it exists before calling .easytabs(). Pretty simple. Thanks!

if ( $( "#tab-container li:first-child" ).length ) {
     $('#tab-container').easytabs(); 
}

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JangoSteve avatar JangoSteve commented on August 20, 2024

Awesome, sounds good. Thanks for the update, @MobsterGit!

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