Comments (4)
The two integers are the (x, y) coordinate of the pixel, with (0, 0) corresponding to the top left of the image
from image.
I'm not really sure what you question is, but pixel
has type &mut Pixel
so you probably want to update it via:
*pixel = pixel.0.map(|_| { 250 })
from image.
Thank you... Each iteration yields the two numbers and the pixel, I don't understand what the numbers are
from image.
Thank you, I'd assumed that but wasn't sure, iteration over rows gives the row and cells so I thought it would have been odd the enumeration over I'm understanding right?
from image.
Related Issues (20)
- Panic when checking broken tiff file HOT 1
- Freeze when trying to open and save jpg and webp files HOT 3
- Random crashes when decoding exr file HOT 2
- `image` still depends on `jpeg-decoder` through the `tiff` crate
- `rayon` is included in the dependency tree even when the `rayon` feature is disabled when `ravif` feature is enabled HOT 1
- The documentation on `crop()` is confusing HOT 1
- Add in-place versions of all rotation operations HOT 1
- `DynamicImage::crop()` is slow because `to_image()` is slow HOT 1
- Cropping API doesn't check bounds, easy to misuse HOT 7
- EnumeratePixels and EnumerateRows should implement DoubleEndedIterator HOT 3
- Implement a `rows()` iterator on `SubImage` HOT 6
- how to convert a rgbaImage to opencv's Mat?
- Regression: Hot lib reload, unable to find __rust_alloc. HOT 6
- Increased generation loss in JPEG encoder HOT 1
- Broken link in docs HOT 2
- Should the next major release be 1.0? HOT 2
- Detect alpha on jpeg HOT 2
- Alternate versions of the crates which allow regular breaking changes HOT 7
- Animated WebP decoding error HOT 8
- “Corrupt RLE data” on simple BMP
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from image.