Comments (4)
To set individual query string parameters, as in your example, use the args
or query_params
parameter of add()
.
>>> from furl import furl
>>> f = furl('http://www.a.de/?a=b')
>>> f.add(args={'x':'z'})
>>> f.url
'http://www.a.de/?a=b&x=z'
args
is also the first parameter of add()
, and thus can be optionally omitted.
>>> f = furl('http://www.a.de/?a=b')
>>> f.add({'x':'z'})
>>> f.url
'http://www.a.de/?a=b&x=z'
Or, all in one line
>>> furl('http://www.a.de/?a=b').add({'x':'z'}).url
'http://www.a.de/?a=b&x=z'
Does that answer your question?
from furl.
I see I didn't specify the problem well enough, sorry! I'm looking for a way to replace parameters that might or might not be already present in the query string. Here's a better example:
>>> furl('http://www.a.de/?page=1').add({'page': '2'}).url
'http://www.a.de/?page=1&page=2
# I actually would like to get 'http://www.a.de/?page=2'
I could use set(), but that removes any other unrelated parameters that are in the query string:
>>> furl('http://www.a.de/?search=foo&page=1').set({'page': '2'}).url
'http://www.a.de/?page=2
# I actually would like to get 'http://www.a.de/?search=foo&page=2'
from furl.
The set()
method of furl
objects sets entire URL components, like the query, in the absolute sense. That is, set()
replaces existing URL components with those provided.
To set individual query parameters with a dictionary-like object, call set()
on the Query
object instead of the parent furl
object.
>>> f = furl('http://www.a.de/?search=foo&page=1')
>>> f.query.set({'page': 2})
>>> f.url
'http://www.a.de/?search=foo&page=2'
To accomplish the aforementioned in one line, combine remove()
and add()
.
>>> from furl import furl
>>> furl('http://www.a.de/?search=foo&page=1').remove(['page']).add({'page': 2}).url
'http://www.a.de/?search=foo&page=2'
Do either of the above satisfy your needs?
from furl.
Yes, thank you :-)
from furl.
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from furl.