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sasha-gitg avatar sasha-gitg commented on July 21, 2024

The resource isn't created until run is invoked. There is an additional line to execute in the example: https://github.com/googleapis/python-aiplatform/blob/main/README.rst?plain=1#L232

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phillies avatar phillies commented on July 21, 2024

Ok, but isn't the behaviour then counterintuitive? I provided e.g. display_name when creating the job. Throwing an error when I want to read what I just created, e.g. job.display_name, is confusing. A hint in the documentation or error message that one must call run() (or submit()) before accessing the object would be helpful.
The same error happens when you execute job.run(sync=False) first and then try to read e.g. display_name.

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